10x^2+40x+40=0

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Solution for 10x^2+40x+40=0 equation: 



10x^2+40x+40=0

a = 10; b = 40; c = +40;
Δ = b2-4ac
Δ = 402-4·10·40
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-40}{20}=-2$

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